&& finally...

Okay.. so both kadeem and i kind of 4got about the blog.. haha.. opps..
but here it is:
2day we went over all the answers 4 the assigned qus. yesterday. the answers + some of the work was (fr. the green book, pg 213):
#1: w=Fd
w = (80N)(10m)
w = 800J

#3: W = 176J
d = 0.3 m
w = Fd ---> F = w/d
= 176/0.3
= 586.6
#5: (0.25)(0.12)(3) + ((0.23-0.12)/2) = 0.145
#8a)
b) w= Fd
= 1319
c) w = -11319J
#10: F = 845N ; d=185m ; w=1.2*10^4 J
w = F cos (feta) d
(feta) = 60 degrees
#12: Now work is done as F 10 is perpendicular to the distance
#17a: F = 9.8*240
#17b: both distance and work = 0
#17c: w = Fd
-5527.25
# 17d: No it does not exert any force
#22a: cos 32 = 805 N/ H
#22b: F = 805N
angle = 32 degrees
w = Fd
w = (805)(22)
w = 17710 J
# 22c: w = 17710
t = 10s
p = w/t
= 2213.75 watts
#23: F(2) = F(1) cos 45
=(42.3)(cos45)
= 29.91N
w = Fd
w = (29.91)(16)
w = 478.56 J

p = w/t
p = 478.56/3
159.52 watts

... wow that took long

&& hw 4 2night is.. 1, 3, 6, 9, 10, 12, 14, 21, 23 on pg 237

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